Less Faster Memory or more Slower Memory?

Discussion in 'Home Networking' started by Jim, Jan 19, 2006.

  1. Jim

    Jim Guest

    I have a 1.2Ghz machine running XP Home. It has 256MB of PC3000 memory.
    I have another 256MB stick of PC2700 and another 256MB stick of 266Mhz
    memory.

    Is it better to stay with only the PC3000 memory or go ahead and add all
    of it at differing speeds?

    Jim
     
    Jim, Jan 19, 2006
    #1
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  2. Jim

    Rob Morley Guest

    What speed is the FSB? That's the best speed to run the RAM at, even if
    it could go faster.
     
    Rob Morley, Jan 19, 2006
    #2
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  3. Jim

    Conor Guest

    PC2700 is the same as 266MHz.
    Stick it all in. The CPU's FSB will be the same/lower than the PC2700
    anyway so the stuff currently in isn't running at its maximum speed.
     
    Conor, Jan 19, 2006
    #3
  4. Jim

    Alex Fraser Guest

    PC2100 is 133MHz DDR, also described as 266MHz.
    PC2700 is 166MHz DDR, also described as 333MHz.
    Your conclusion is probably correct.

    Alex
     
    Alex Fraser, Jan 19, 2006
    #4
  5. Jim

    Conor Guest

    LOL. My bad.
     
    Conor, Jan 19, 2006
    #5
  6. Jim

    Jim Guest

    Alex Fraser wrote on 1/19/2006 4:12 PM:
    I went back and double checked. This was a PC I ended up giving to my
    kids. The Mobo supports 333Mhz memory. The speed difference between 266
    and 333 cant be that great. The processor is an Athlon XP 1.1Ghz. The
    board supports up to 2Ghz process so I may just up the CPU to extend the
    life.

    Thanks for all your feedback.

    Jim
     
    Jim, Jan 20, 2006
    #6
  7. Jim

    Dave J. Guest

    Alex, could you (or for that matter anyone) tell me the origin of the
    numbering? What I mean is there isn't an obvious mathematical link between
    '2100' and 266, nor between 2700 and 333.

    Maybe there is a link and I can't see it?
     
    Dave J., Jan 21, 2006
    #7
  8. Jim

    John Fryatt Guest

    266 is the speed in MHz and 2100 is the data transfer rate.
    8 bytes of data are transferred across the bus at a time

    So, 8 bytes x 266MHz = 2128Bps (rounded to 2100)

    and 8 * 333 = 2664 (2700)
     
    John Fryatt, Jan 21, 2006
    #8
  9. Jim

    Jim Guest

    Jim wrote on 1/19/2006 1:45 PM:
    The additional memory made a Big difference. Also, I posted something
    similar in the OS.windows.xp NG with no responses whatsoever.

    Interestingly, I started looking in to it. To take that PC (Kids are
    ages 6 and 9)to a 1GB 333Mhz RAM and a 2Ghz CPU, it would cost me $200.
    If you keep your eye open, you can get a brand new Dell for $400 with
    flat screen monitor.

    Thanks again guys!!

    Jim
     
    Jim, Jan 21, 2006
    #9
  10. Jim

    Conor Guest

    No it isn't.
     
    Conor, Jan 21, 2006
    #10
  11. Jim

    Dave J. Guest

    OK. Would you mind explaining what it is then?
     
    Dave J., Jan 21, 2006
    #11
  12. Jim

    John Fryatt Guest

    Alright, I'm willing to be corrected. Maybe you would deign to explain?
     
    John Fryatt, Jan 21, 2006
    #12
  13. Jim

    Rob Morley Guest

    The bus speed is 133MHz - the RAM is clock-doubled :)
     
    Rob Morley, Jan 21, 2006
    #13
  14. Jim

    Dave J. Guest

    In MsgID<> within
    uk.comp.home-networking, 'Rob Morley' wrote:

    [...]
    Yes, so 133 is the clock frequency but 266 is the RAM clock speed.

    That's what I picked up on courtesy of John's message. In fact given the
    words he used, John was exactly right. The part I was stupidly missing out
    on in looking for correlation was conversion between bitrate and byterate,

    John never said a word about clock frequency. If the module is responding
    to both edges of the clock (which I believe is the MO of clock doubling
    though ICBW) then the speed *is* twice the frequency.

    Of course I should have looked it up for myself as a quick search soon
    confirmed it.

    Would have been interesting to see Conor try to elaborate on his unhelpful
    'contribution'

    Dave J.
     
    Dave J., Jan 22, 2006
    #14
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