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#1
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> I spent 2 hours on the phone with netgear. They had me trying all sorts > of stuff. Forcing 5.5Mbps. Forcing 11Mbps. You do realize of course, that 11Mbps is 5.5 in each direction, right? It's not 11Mbps in one direction, going both ways. |
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#2
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> You do realize of course, that 11Mbps is 5.5 in each direction, right? > > It's not 11Mbps in one direction, going both ways. Sorry, misinformation. The signalling rate is 11Mbps period. What you get in terms of throughput from a half duplex system once you add on protocol overhead is something completely different. It's 11Mbps in either direction but not at the same time. That's quite different from 5.5 each way. ![]() David. |
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#3
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On Mon, 23 Jun 2003 14:23:15 +0100, David Taylor wrote: > What you get in terms of throughput from a half duplex system once you > add on protocol overhead is something completely different. Now now, let's not spread more misinformation. 802.11b is NOT half-duplex, it's TDD (Time Division Duplexing). This means that the radio must switch between transmit (Tx) and receive (Rx). The checksums in 802.11b are not transmitted over the air. A checksum is performed in the MAC and if a packet does not pass, no ACK is sent back to the transmitter. For 802.11b (which has a theoretical peak and total bandwidth of 11Mbps) you could either send or receive 11Mbps in "half-duplex" mode or switch to a "full-duplex" type of operation that lets you send at 5.5Mbps and receive 5.5Mbps simultaneously, or any mixture that totals 11 Mb. You cannot send TCP traffic at more than 5.5Mbps on 802.11b, because you still need that amount of ACK coming back. If you want to send at 9Mbps outbound, you need enough in the protocol to allow 9Mbps back, i.e. 18Mbps, which 802.11b is not. |
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#4
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So I should be getting 5.5Mbps. I'm getting 2.3Mbps. Where's the difference? Interference? Thanks. Ryan "John Doe" <(E-Mail Removed)> wrote in message news:<(E-Mail Removed)>... > On Mon, 23 Jun 2003 14:23:15 +0100, David Taylor wrote: > > > What you get in terms of throughput from a half duplex system once you > > add on protocol overhead is something completely different. > > Now now, let's not spread more misinformation. 802.11b is NOT > half-duplex, it's TDD (Time Division Duplexing). This means that the radio > must switch between transmit (Tx) and receive (Rx). The checksums in > 802.11b are not transmitted over the air. A checksum is performed in the > MAC and if a packet does not pass, no ACK is sent back to the transmitter. > > For 802.11b (which has a theoretical peak and total bandwidth > of 11Mbps) you could either send or receive 11Mbps in "half-duplex" mode > or switch to a "full-duplex" type of operation that lets you send at > 5.5Mbps and receive 5.5Mbps simultaneously, or any mixture that totals 11 > Mb. You cannot send TCP traffic at more than 5.5Mbps on 802.11b, because > you still need that amount of ACK coming back. If you want to send at > 9Mbps outbound, you need enough in the protocol to allow 9Mbps back, i.e. > 18Mbps, which 802.11b is not. |
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#5
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> Now now, let's not spread more misinformation. 802.11b is NOT > half-duplex, it's TDD (Time Division Duplexing). This means that the radio Ok, splitting hairs, TDD and half duplex are the same thing. Half duplex, transmit/receive but only in one direction at a time. > For 802.11b (which has a theoretical peak and total bandwidth > of 11Mbps) you could either send or receive 11Mbps in "half-duplex" mode No theory about it, the signalling rate *IS* 11Mbps. > or switch to a "full-duplex" type of operation that lets you send at > 5.5Mbps and receive 5.5Mbps simultaneously, So tell me, how are you going to do that simultaneously with a single radio... > you still need that amount of ACK coming back. If you want to send at > 9Mbps outbound, you need enough in the protocol to allow 9Mbps back, i.e. > 18Mbps, which 802.11b is not. If what you suggest were true, any asymmetric connection such as ADSL would need to have the same upstream bandwidth and well, it doesn't. David. |