recv() till particular string

Dear all,

I have an application where the client receives message from
server,but the problem is i need to receive message till a particular
string arrives in the stream the client is getting.Is it possible to
use recv() systems call to do this or is there any other way.

Please help me.

Hi, Harry_1

use a data-buffer, each time recv() returns, add-copy data to the buffer,
then try find the "particular string" in the buffer (for performance
consideration, you needn't find it from the head of the whole buffer each
time);
if found then return the data in the buffer.
else select() for more data to read

may it works, but a little hard to implementation.

yours sincely

Harry_2


"Harry" <(E-Mail Removed)>
??????:(E-Mail Removed) roups.com...
> Dear all,
>
> I have an application where the client receives message from
> server,but the problem is i need to receive message till a particular
> string arrives in the stream the client is getting.Is it possible to
> use recv() systems call to do this or is there any other way.
>
> Please help me.
>

In article <(E-Mail Removed). com>,
(E-Mail Removed) (Harry) writes:

> I have an application where the client receives message from
> server,but the problem is i need to receive message till a particular
> string arrives in the stream the client is getting.Is it possible to
> use recv() systems call to do this or is there any other way.

Given a TCP/IP connection, recv() is the only way. Any routine that
appears to be otherwise is merely a wrapper around recv(). There is
no data sensitivity; the data is viewed as nothing more than a string
of bytes, and recv() gets as much as it can. If you're looking for
a particular string, there's not even a guarantee that one call to
recv() will even receive all of it. For instance, if you're looking
for "foo", the first time you call recv() you might just receive "fo".
The next time you call recv() there might be nothing ready, and the
third time you might finally receive the final "o" (plus any further
bytes which might be coming through).

So no, there is no simple solution. You'll have to write a routine
that's smart enough to concatenate chunks of data, while checking
whether the result contains what you're looking for. Take heart;
it's not as hard as it seems.

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