On 10 Oct 2005 14:13:41 -0700,
(E-Mail Removed) wrote:
>X-No-Archive
Why?
>I meant Noise Figure of 10dB. I read in different articles that NF of
>5-10 dB is considered for systems based on IEEE 802.11 WLAN.
Read again. 10dB is a tolerable number for the *SYSTEM* noise figure
which includes everything between the antenna and the demodulator. The
actual minimum acceptable noise figure is heavily dependent on the
type of modulation, data speed, and desired BER (bit error rate). My
guess(tm) is that the 10dB figure is for a BPSK 1-2 Mbit 802.11
system. This doesn't apply to an ODFM 802.11a system.
>The problem is that if only thermal noise will be considered as the
>noise source in the system the noise power density will be around
>10^(-20) and as a result SNR at locations even far from AP will be very
>high!
Well, I can't check your calculations without seeing them first. I'm
also not going to try and reproduce your calculations without the
slightest clue as to which system parameters you're using, and which
assumptions you're making. However, I do have a guess. The usual
mistake is to forget to include the 10dB minimum (FCC required) spread
spectrum processing gain.
>For example if we calculate the received power[dB] as transmit power
>minus path loss minus noise power,
You forgot the antenna gains and coax losses.
You can subtract the noise power but getting a value of noise power is
a bit tricky as it's affected by the noise figure of the receiver
front end. If you're using the occupied bandwidth of the spread
spectrum signal as your noise power bandwidth, you're doing it wrong.
Think digital filter and demodulator bandwidth.
I suggest you switch to using the receiver sensitivity at a reference
BER, which will yield a corresponding S/N ratio at the demodulator
depending on modulation type and speed. Model the system from the
transmitter to the receiver input seperately from the receiver input
to the demodulator output.
>considering the 802.11a parameters
>(carrier frequency at 5 GHz and transmit power of 100 mW) with path
>loss exponent of 3 at distance of 20m from the AP
5GHz or 5.7GHz?
Path loss is measured in dB and is easily calculated.
http://www.microindustrie.com/fcc/path.htm
I'm too lazy to work the numbers.
Path loss exponent is used to determine the variation in path loss
caused by various edge obstructions and atmospherics and should not
enter into your equation unless you're looking for a worst case
analysis or doing interior reflective ray tracing. The value is also
empirically derived somewhat of a guess. At this point, I have no
clue as to why you introduced loss exponent.
>the SNR will be
>around 20dB! Compared to reality this is too high!
The system noise figure and the minimum demodulated S/N ratio are not
the same number. The S/N ratio is more commonly related to the
modulation type and the BER.
I have a feeling this is your homework project. I don't mind helping
but most schools have better resources available. If you would kindly
disclose:
1. What you're trying to accomplish?
2. What you have to work with?
I'll try to be more helpful.
--
Jeff Liebermann
(E-Mail Removed)
150 Felker St #D
http://www.LearnByDestroying.com
Santa Cruz CA 95060
http://802.11junk.com
Skype: JeffLiebermann AE6KS 831-336-2558