(E-Mail Removed) hath wroth:
>Maintaining a fresnel zone as computed on this website seems darn near
>impossible in most situations. Is this independent of polarization?
It's mostly independent of polarization. By mostly, I mean that there
are some differences. The effect of encroaching on the Fresnel Zone
is that the object creates edge diffraction, which redirects the
signal out of the line connecting the RF source and receiver. The
degree of edge diffraction is polarization sensitive, where horizontal
object tend to diffract a verically polarized signal more than
horizontal. However, the effect is not huge and for initial
calculations, it should be considered polarization independent.
It's NOT impossible for most situations. For example, at a range of
300ft (the alleged maximum range of conventional wireless), the 80%
Fresnel Zone radius is only 4.4 ft. That's easily achievable.
Where it gets difficult is for long range links. For example, at 5
miles, the midspan clearance should be 42 ft. In effect, that means
that both antennas at the link ends must be at least 42 ft off the
ground level or the ground will end up inside the 80% Fresnel Zone.
Actually, it's somewhat higher than 42 ft because of the curvature of
the earth. Also note that this is only at the midpoint of the link.
As you get closer to each end, the required clearance becomes less.
>What frequency range is valid for this website?
The Fresnel Zone varies with the inverse square of the frequency:
Midpoint clearance in ft = 72.1 * sqrt(D/4f)
D = distance in miles.
f = frequency in GHz.
It breaks down at extremely low frequencies due to the inability to
find a sufficiently large clearance area. At the high end, it starts
to involve optical effects (fringing, scatter, speckle, interference
patterns, etc) at about 22GHz. I would guess(tm) that the simple
approximation is valid from about 500MHz to 22GHz. It's also a far
field calculation that will break down for short distances which
involve near field calculations.
This online calculator seems a bit more useful for calculating
required clearance for various objects along the path:
|
http://www.ratrivertech.ca/archives/...Calculator.htm
--
Jeff Liebermann
(E-Mail Removed)
150 Felker St #D
http://www.LearnByDestroying.com
Santa Cruz CA 95060
http://802.11junk.com
Skype: JeffLiebermann AE6KS 831-336-2558