Linux bash syntax Q:

Im posting here cuz I know you guys know!
Is there a simple way to route standard out to the parameter of a second
command...
like say you want to find a file and then less it.
something like: locate peanut.txt | less <stdin>

thanks guys!

On Thu, 13 Jan 2005 08:56:24 +0200, Coenraad Loubser
<(E-Mail Removed)> wrote:
> Im posting here cuz I know you guys know!
> Is there a simple way to route standard out to the parameter of a second
> command...
> like say you want to find a file and then less it.
> something like: locate peanut.txt | less <stdin>
>
locate peanut.txt | xargs less


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In article <cs55vr$anl$(E-Mail Removed)>, Coenraad Loubser wrote:

>Im posting here cuz I know you guys know!
>Is there a simple way to route standard out to the parameter of a second
>command...

http://tldp.org/guides.html

Dec 6 13:54 Bash-Beginners-Guide
Nov 15 08:41 abs-guide

>like say you want to find a file and then less it.
>something like: locate peanut.txt | less <stdin>

backquotes - the ones to the left of the '1' key on most keyboards.

less `locate peanut.txt`

That says take the output of the locate command and feed that to 'less'
as an argument. This is different from 'locate peanut.txt | less' which
would display the text that locate found (filenames).

Old guy

Coenraad Loubser wrote:
> Im posting here cuz I know you guys know!
> Is there a simple way to route standard out to the parameter of a second
> command...
> like say you want to find a file and then less it.
> something like: locate peanut.txt | less <stdin>
>
> thanks guys!

Try:
find <whatever> -exec less {} \;


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