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Dual Ethernet cards is there a HOWTO for this?

 
 
The Eighth Doctor
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      11-09-2005, 03:17 AM
Hello from the confused Timelord
It seems for one of my less then stellar customers I need to setup a Linux box, that
will be wearing two Ethernet cards. The first one is native, IE, it came on the
motherboard of the host. The second one is a relatively cheap card that I'll be
installing. My chosen distribution Slackware, contains in its rc.d scrips references to
eth0, and eth1, and others so this tells me that it will cooperate with the concept. But
does a HOWTO exist, besides the regular one on Ethernet for doing this?

Incidentally I am not going to be repeating this on the newsgroup for Slackware.
There's a malignant troll over there who does not know how to stop being insulting.
I don't want to do two things, name names, and explain further.
----
Gregg drwho8 atsign att dot net
"This signature says "GRONK!" repeatedly.**

 
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Bit Twister
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      11-09-2005, 03:54 AM
On Wed, 09 Nov 2005 04:17:29 GMT, The Eighth Doctor wrote:
> Hello from the confused Timelord


How about setting WinVN to line wrap at 72 characters. That allow for
indention indicators.

> It seems for one of my less then stellar customers I need to setup a
> Linux box, that will be wearing two Ethernet cards. The first one is
> native, IE, it came on the motherboard of the host. The second one
> is a relatively cheap card that I'll be installing. My chosen
> distribution Slackware, contains in its rc.d scrips references to
> eth0, and eth1, and others so this tells me that it will cooperate
> with the concept.


Yep, linux distribution poll the buss and the first nic found becomes
eth0, second becomes eth1,....

You pick eth1 to configure instead of eth0. What is "this" that you
are trying to do.

> But does a HOWTO exist,


Yes.

> besides the regular one on Ethernet for doing this?


http://tldp.org has a search box.

You might want to read
http://www.catb.org/~esr/faqs/smart-questions.html
if you are trying to get answers for a specific question.


and do bookmark this very large, Frequently Asked Questions (faq) search engine
http://groups.google.com/advanced_group_search
key words(s) in the first box
*linux* in Newsgroup box. You need to use the two
asterisks around linux, pick English


> Incidentally I am not going to be repeating this on the newsgroup
> for Slackware.


Net etiquette/Newsgroup tip:

Multi-posting is considered antisocial on Usenet.

If you want to send the same message to more than one newsgroup, CROSSPOST!
And if you crosspost, provide a Followup newsgroup.

Some will argue that you not even crosspost because of the amount/type
of newsgroups that we have today.

As an example to post to "comp.os.linux.security", and
"alt.security", use the following Newsgroups line:
Newsgroups: comp.os.linux.security,alt.security
Followup-To: comp.os.linux.security

See http://www.cs.tut.fi/~jkorpela/usenet/xpost.html

 
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Unruh
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      11-09-2005, 06:08 AM
drwho8__NOTME__@att.net (The Eighth Doctor) writes:

>Hello from the confused Timelord
>It seems for one of my less then stellar customers I need to setup a Linux box, that
>will be wearing two Ethernet cards. The first one is native, IE, it came on the
>motherboard of the host. The second one is a relatively cheap card that I'll be
>installing. My chosen distribution Slackware, contains in its rc.d scrips references to
>eth0, and eth1, and others so this tells me that it will cooperate with the concept. But
>does a HOWTO exist, besides the regular one on Ethernet for doing this?




No idea, but the process is not hard, except for the problem of making sure
each time that the right ethernet card gets associated with the right eth?
name.
Basically the first one found (probably the motherboard card) will be eth0
and the other eth1.
Then you need to tell the cards what their IP addresses are and what the
routes you want going through the various cards.

On many distros (I do not know Slack) there is an executable called
ifup
to which you can give the name of the eth port you want. On Mandrake it
reads /etc/sysconfig/network-scripts/ifcfg-eth0 or ifcfg-eth1 to tell is
the IP addresses gateways, etc.
 
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The Eighth Doctor
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      11-10-2005, 03:16 AM
In article <dks79v$moo$(E-Mail Removed)>, unruh-(E-Mail Removed)
says...
>
>drwho8__NOTME__@att.net (The Eighth Doctor) writes:
>
>>Hello from the confused Timelord
>>It seems for one of my less then stellar customers I need to setup a Linux box,

that
>>will be wearing two Ethernet cards. The first one is native, IE, it came on the
>>motherboard of the host. The second one is a relatively cheap card that I'll be
>>installing. My chosen distribution Slackware, contains in its rc.d scrips references

to
>>eth0, and eth1, and others so this tells me that it will cooperate with the concept.

But
>>does a HOWTO exist, besides the regular one on Ethernet for doing this?

>
>
>
>No idea, but the process is not hard, except for the problem of making sure
>each time that the right ethernet card gets associated with the right eth?
>name.
>Basically the first one found (probably the motherboard card) will be eth0
>and the other eth1.
>Then you need to tell the cards what their IP addresses are and what the
>routes you want going through the various cards.
>
>On many distros (I do not know Slack) there is an executable called
>ifup
>to which you can give the name of the eth port you want. On Mandrake it
>reads /etc/sysconfig/network-scripts/ifcfg-eth0 or ifcfg-eth1 to tell is
>the IP addresses gateways, etc.


Hello from Gregg C Levine
Okay. I'll look into it. If not, I'll port it over from one of the others. I've stuck a
second card into the other box.

And there's nothing wrong with the way WinVN composes what I type. If nothing
else there might be something wrong your newsreader. Oh, and why should I visit a
collection of useless advice? There are plenty of examples of useless advice and
stupid questions out there. Some even in this newsgroup. I didn't state what you
think I did. I stated that I would not be doing that.
--
Gregg drwho8 atsign att dot net
"This signature disavows itself of its own existence."

 
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