On 17 Mar 2005 12:49:02 -0800,
(E-Mail Removed) wrote:
>My sister live by Gilroy, and I would trade that for the smell of
>ammonia anytime.
You haven't smelled ammonia until you've worked in a cannery with
rotting fish smell. She has it easy in Gilroy. Most of the garlic
fields have been converted to housing and industrial tracts. However,
King City is miles and miles of garlic. They intentionally hold the
Gilroy Garlic Festival well before the actual harvest time.
>Yea, the only thing I don't like is port 23 is kept open, hopefully my
>ZAlarm firewall is doing it's job.
It shouldn't be a problem on your PC. Just run:
netstat -n
in an MSDOS window. The "Local Address" column shows all the port
numbers that are open. As long as you're not running a telnetd server
on port 23, it's not a problem.
>Belkin, the price was right. With rebates, we'll see if they come back,
>it was only 20 bucks from Comp(ripoff)USA.
We're lucky. We don't have a local CompUSA. Circuit City is the best
we can do. They don't carry Belkin. The local Office Max carries
Belkin, Linksys, and Dlink to cover everyone's prejudices.
>That's good. Easy for my simple brain to understand. When I use
>netstumbler, I get negative numbers. How can one have a negative dB
>reading? If you're transmitting, isn't that a signal in positive
>mWatts?
Nope. The "m" in dBm is "milliwatt". The numbers you're seeing are
releative to 1.0 milliwatts or 0dBm. If you were talking about power
output from a transmitter, then it would be decibels above 1
milliwatt. For example, 100 milliwatts is 100 times more than 1
milliwatt. So, the math is:
dBm = 10 * log (ratio)
dBm = 10 * log (100) = +20dBm
However, receive signals are usually less than 1 milliwatt, the ratio
becames a fraction, and therefore the dBm values are negative. If the
receiver hears a signal at 100 microwatts [1], then that's 1/1000th of
the 1 milliwatt signal or:
dBm = 10 * log (ratio)
dBm = 10 * log (1/1000) = -30dBm
[1] Receive signal is usually not described in microwatts but is
either converted to dBm as above or expressed in microvolts across a
50 ohm load:
100E-6 watts = (Voltage)^2 / 50 ohms
100E-6 = E^2 / 50
E = 0.7E^-3 = 700 microvolts.
--
# Jeff Liebermann 150 Felker St #D Santa Cruz CA 95060
# 831.336.2558 voice
http://www.LearnByDestroying.com
#
(E-Mail Removed)
#
(E-Mail Removed) AE6KS