> 172.16.8.0 - 172.16.11.255 = 172.16.8.0/22 which is a mask of 255.255.252.0
> and so on. Is 172.16.8.1 the IP address of the router that has access to
> all of those networks, or is it the address of "this" interface card? What
> is in the file /etc/sysconfig/network-scripts/route-eth0 ?
My IP: 172.16.9.219, 172.16.8.1 is IP of the router of LAN.
File route-eth0:
GATEWAY1=172.16.8.1
NETMASK1=255.0.0.0
ADDRESS1=10.0.0.0
GATEWAY0=172.16.8.1
NETMASK0=255.255.0.0
ADDRESS0=172.16.0.0
> >Using one I can access other as well, but I want to use 2 networks.
>
> This is not understandable. Is _this_ host meant to be a router? If so,
> edit /etc/sysconfig/network and set the variable "FORWARD_IPV4=true"
I mean how to config my box using command "route".
Our LAN has some domain: local (from 172.16.8.x-172.16.31.x), hackers
(from 172.16.32.x - 172.16.63.x), and others 10.x.x.x. I've connected
my box to both local and hackers, but in fact using only one connect
(local or hackers) can access to almost LAN resources. But there's
competition between 2 domains (local, hackers), thus some resources
only can be accessed by computers that have defined domain.