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192.168.0.0 into 2 subnets how

 
 
stewart menday
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      12-18-2003, 10:54 PM
Hi all
I wish to brake the 192.168 network into 2 equal subnets what would be
ip ranges for these subnets and what would be there net mask?

Thanks

Stewart


 
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Michael Buchenrieder
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      12-19-2003, 06:27 AM
"stewart menday" <stewart at webstorm.net.au> writes:

>Hi all
> I wish to brake the 192.168 network into 2 equal subnets what would be
>ip ranges for these subnets and what would be there net mask?



I think you want to RTF RFC1878.

Michael

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Mike Vore
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      12-19-2003, 04:02 PM
On Fri, 19 Dec 2003 10:54:57 +1100, stewart menday <> wrote:
>
>
> Hi all
> I wish to brake the 192.168 network into 2 equal subnets what would be
> ip ranges for these subnets and what would be there net mask?
>


You wan two "B/2" (17bit) nets?
192.168.0.0 255.255.128.0 192.168.0.0 -> 192.168.127.255
192.168.120.0 255.255.128.0 192/168.128.0 -> 192.168.255.255


But if yo uwan two "C/2" (25bit) as your Subject line asks
192.168.0.0 255.255.255.128 192.168.0.0 -> 192.168.0.127
192.168.0.128 255.255.255.128 192.168.0.128 -> 192.168.0.255


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jack
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      12-19-2003, 05:20 PM
Mike Vore wrote:
> On Fri, 19 Dec 2003 10:54:57 +1100, stewart menday <> wrote:
>
>>
>>Hi all
>> I wish to brake the 192.168 network into 2 equal subnets what would be
>>ip ranges for these subnets and what would be there net mask?
>>

>
>
> You wan two "B/2" (17bit) nets?
> 192.168.0.0 255.255.128.0 192.168.0.0 -> 192.168.127.255
> 192.168.120.0 255.255.128.0 192/168.128.0 -> 192.168.255.255
>
>
> But if yo uwan two "C/2" (25bit) as your Subject line asks
> 192.168.0.0 255.255.255.128 192.168.0.0 -> 192.168.0.127
> 192.168.0.128 255.255.255.128 192.168.0.128 -> 192.168.0.255


UUaarrgghh!!,

Sorry for shouting, but all strings "128" should read "254" here!

You cut bits from right to left.


Cheers, Jack.

--
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My personal reading of the string "MicroSoft" expands to "NanoWeak"...

 
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Jim Fischer
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      12-19-2003, 08:52 PM
Michael Buchenrieder wrote:
> "stewart menday" <stewart at webstorm.net.au> writes:
>
>
>>Hi all
>> I wish to brake the 192.168 network into 2 equal subnets what would be
>>ip ranges for these subnets and what would be there net mask?

>
>
>
> I think you want to RTF RFC1878.


.... and then find yourself a handy-dandy IP address calculator, e.g.

http://jodies.de/ipcalc

FWIW, I found this site via Google (http://www.google.com) web search
using the keywords

ip address subnet supernet calculator

--
Jim

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jfischer_link5809{at}now.here.com


 
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Rich Grise
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      02-15-2004, 10:39 PM
Are you sure of that? When I write the ips and netmasks in binary,
it looks like substituting "254" for "128" in all cases would give
you one subnet with about 252 nodes and one with 2, which would
be unusable, since one's the whole network (254) and the other is
broadcast (255).

I'm sure some fine neighbor will enlighten us if I'm in error.

Thanks
Rich

"jack" <(E-Mail Removed)> wrote in message
news:brvfhv$j51$06$(E-Mail Removed)...
> Mike Vore wrote:
> > On Fri, 19 Dec 2003 10:54:57 +1100, stewart menday <> wrote:
> >
> >>
> >>Hi all
> >> I wish to brake the 192.168 network into 2 equal subnets what would

be
> >>ip ranges for these subnets and what would be there net mask?
> >>

> >
> >
> > You wan two "B/2" (17bit) nets?
> > 192.168.0.0 255.255.128.0 192.168.0.0 -> 192.168.127.255
> > 192.168.120.0 255.255.128.0 192/168.128.0 -> 192.168.255.255
> >
> >
> > But if yo uwan two "C/2" (25bit) as your Subject line asks
> > 192.168.0.0 255.255.255.128 192.168.0.0 -> 192.168.0.127
> > 192.168.0.128 255.255.255.128 192.168.0.128 -> 192.168.0.255

>
> UUaarrgghh!!,
>
> Sorry for shouting, but all strings "128" should read "254" here!
>
> You cut bits from right to left.
>
>
> Cheers, Jack.
>
> --
> ----------------------------------------------------------------------
> My personal reading of the string "MicroSoft" expands to "NanoWeak"...
>



 
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Johan Lindquist
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      02-15-2004, 10:56 PM
So anyway, it was like, 00:39 CET Feb 16 2004, you know? Oh, and, yeah,
Rich Grise was all like, "Dude,

> it looks like substituting "254" for "128" in all cases would give
> you one subnet with about 252 nodes and one with 2, which would
> be unusable, since one's the whole network (254) and the other is
> broadcast (255).


A 255.255.255.254 netmask gives you a pretty small subnet indeed.

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